Methoxyflurane | C3H4Cl2F2O | ChemSpider

N2F2 has 24e-, therefore you need to have 24 electrons around its Lewis Structure: F-N=N-F > each covalent bond has 2 electrons, so we have 8 here, then add 3 lone pairs to each F atom, and 1 lone...That's all you need to know to answer this) , you know that first of all you have to draw the Lewis structure of the compound, which you can draw like this and now you have got the preliminary linear structure of the molecule $\ce{N2F2}$. Here, FYI, there might be a mistake. It can be done by considering $\ce{N2F2}$ to be analogues to $\ce{NF3